Calculate the pressure of 2.78 g of Ne in a 5.00 L flask at -10°C

0.60 atm

Explanation:

Step 1.

Data obtained from the question.

This includes the following:

Mass of Ne = 2.78g

Volume (V) = 5L

Temperature (T) = –10°C

Pressure (P) =?

Step 2:

Determination of the number of mole of Ne.

The number of mole of Ne can be obtained as follow:

Mass of Ne = 2.78g

Molar Mass of Ne = 20g/mol

Number of mole Ne =?

Number of mole = Mass/Molar Mass

Number of mole of Ne = 2.78/20

Number of mole of Ne = 0.139 mol

Step 3:

Conversion of celsius temperature to Kelvin temperature. This can be achieved by as shown below:

Temperature (Kelvin) = temperature (celsius) + 273

Temperature (celsius) = –10°C

Temperature (Kelvin) = –10°C + 273

Temperature (Kelvin) = 263K

Step 4:

Determination of the pressure. The pressure can be obtained by using the ideal gas equation as follow:

PV = nRT

Volume (V) = 5L

Temperature (T) = 263K

Number of mole (n) of Ne = 0.139mol

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =?

PV = nRT

P x 5 = 0.139 x 0.082 x 263

Divide both side by 5

P = (0.139 x 0.082 x 263) /5

P = 0.60 atm

Therefore the pressure is 0.60 atm

Option (a) is the correct answer.

Explanation:

An independent variable is defined as a variable whose value or which is controlled in a scientific experiment. Basically, an independent variable is able to change the value of dependent variable.

The value of an independent variable can be changed by the experimenter.

For example, nature of substances in a chemical reaction will act as an independent variable.

This is because if a substance is reactive in nature then in the presence of another substance cannot become unreactive. Hence, nature of a substance is an independent variable.

Thus, we can conclude that out of the given options the nature of the substances is the independent variable.