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Babebrooks9667
05.06.2020 •
Chemistry
Calculate the theoretical yield and percent yield for this experiment
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Ответ:
A. Theoretical yield of KCl is 36.49g
B. Percentage yield of KCl is 90.4%
Explanation:
The balanced equation for the reaction is given below:
2KCLO3 —> 2KCl + 3O2
Next, we shall determine the mass KClO3 that decomposed and the mass KCl produce from the balanced equation. This is illustrated below:
Molar mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol
Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g
Molar mass of KCl = 39 + 35.5 = 74.5g/mol
Mass of KCl from the balanced equation = 2 x 74.5 = 149g.
From the balanced equation above,
245g of KClO3 decomposed to produce 149g of KCl.
A. Determination of the theoretical yield of KCl. This is illustrated below:
From the balanced equation above,
245g of KClO3 decomposed to produce 149g of KCl.
Therefore, 60g of KClO3 will decompose to produce = (60 x 149)/245 = 36.49g of KCl.
Therefore, the theoretical yield of KCl is 36.49g
B. Determination of the percentage yield of KCl. This can be obtaine as follow:
Actual yield = 33g
Theoretical yield = 36.49g
Percentage yield =..?
Percentage yield = Actual yield /Theoretical yield x 100
Percentage yield = 33/36.49 x 100
Percentage yield of KCl = 90.4%
Ответ:
202?
Explanation: