jojojolie8570
19.04.2021 •
Chemistry
Calculate the value of the equilibrium constant for the following system, where the concentrations of reactants and products are: [NO]=1.2x10^-3M , [NO2]=1.5x10-^1M , [N2O]=2.4x10^-3M
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Ответ:
The equilibrium constant is 2.08x10⁵
Explanation:
Based on the reaction:
3NO ⇄ N₂O + NO₂
The equilibrium constant, k, is defined as:
k = [NO₂] [N₂O] / [NO]³
Where the [] is the molarity in equilibrium of each specie.
Computing te values of the problem:
k = [1.5x10⁻¹M] [2.4x10⁻³M] / [1.2x10⁻³M]³
k = 2.08x10⁵
The equilibrium constant is 2.08x10⁵Ответ: