Complete and balance the molecular equation for the reaction of aqueous ammonium bromide, nh4br,
and aqueous lead(ii) acetate, pb(c2h3o2)2. include physical states.

Molecular equation:

2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) →2NH₄C₂H₃O₂(aq) + PbBr₂(s)

Explanation:The molecular equation of the reaction between aqueous ammonium bromide and aqueous lead (ii) acetate is given by;

2NH₄Br(aq) + Pb(C₂H₃O₂)₂(aq) →2NH₄C₂H₃O₂(aq) + PbBr₂(s)

This is an example of a double displacement reaction where two ionic compounds exchange ions with each other to form two new compounds or salts.It can also be a precipitation reaction due to the formation of precipitate from two ionic compounds. Lead(ii) bromide is the precipitate formed during the reaction. The net ionic equation for the reaction is;

2Br⁻(aq) + Pb²⁺(aq)→ PbBr₂(s)

element

Explanation:

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