TrudnEli1217
11.12.2019 •
Chemistry
Consider a solution containing 3.54 mm of an analyte, x, and 1.23 mm of a standard, s. upon chromatographic separation of the solution peak areas for x and s are 3275 and 10829, respectively. determine the response factor for x relative to s.f= determine the concentration of x in an unknown solution, 1.00 ml of 8.27 mm s was added to 5.00 ml of the unknown x solution and the mixture was diluted to 10.0 ml. after chromatographic separation, this solution gave peak areas of 5389 and 4627 for x and s, respectively. determine the concentration of s in the 10.0 ml solution.[s]= the concentration of x in the 10.0 ml solution.[x]= the concentration of x in the unknown solution.[x]=
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Ответ:
S.F = 0,105
[S] = 0,827mM
[X] = 9,17mM in the 10,0mL solution.
18,3mM in the unknown solution
Explanation:
The response factor of X is:
RF x = peak area / concentration = 3275 / 3,54 = 925
And for S is:
RF s = 10829 / 1,23 = 8804
The response factor for X relative to S is:
S.F = 925/8804 = 0,105
As the dilution of the measured solution regard the 8,27mM is 1/10, concentration of S in the unknown solution is:
8,27mM× 1,00mL / 10,0mL= 0,827mM
Using the RRF formula:
Conc X = Peak area X* Concentration B / peak area S * RRF
[X] = 5389*0,827mM / 4627*0,105
[X] = 9,17mM in the 10,0mL solution.
As the dilution of the measured solution regard with unkown solution is 10,0mL / 5,00 mL, in the unknown solution the concentration is:
9,17mM× 10,0mL / 5,00mL =
18,3mM in the unknown solution
I hope it helps!
Ответ: