Chemistry: Consider the following reaction: . so2cl2(g)⇌so2(g)+cl2(g) . a reaction mixture is made containing an initial [so2cl2] of 2.2×10−2m . at equilibrium, [cl2]= 1.3×10−2m .. calculate the value of the equilibrium constant (kc).

Consider the following reaction: . so2cl2(g)⇌so2(g)+cl2(g)

Ответ:

louiecampos

13.01.2022

Chemistry

Answer : The the value of equilibrium constant is, $1.87\times 10^{-2}$

Solution : Given,

Concentration of SO_2Cl_2 = $2.2\times 10^{-2}M$

Concentration of Cl_2 = $1.3\times 10^{-2}M$

The given balanced equilibrium reaction is,

$SO_2Cl_2(g)\rightleftharpoons SO_2(g)+Cl_2(g)$

Initially $2.2\times 10^{-2}M$ 0 0

At eqm,

The concentration of SO_2Cl_2 = $(2.2\times 10^{-2}-1.3\times 10^{-2})M=0.9\times 10^{-2}M$

The concentration of Cl_2 = $1.3\times 10^{-2}M$

The concentration of SO_2 = $1.3\times 10^{-2}M$

The expression for equilibrium constant will be,

$K_c=\frac{[SO_2]\times [Cl_2]}{[SO_2Cl_2]}$

Now put all the given values in this formula, we get

$K_c=\frac{(1.3\times 10^{-2})\times (1.3\times 10^{-2})}{(0.9\times 10^{-2})}$

$K_c=1.87\times 10^{-2}$

Therefore, the value of equilibrium constant is, $1.87\times 10^{-2}$

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Ответ:

Katy3613

01.06.2021

Chemistry

$1,495.92

Explanation:

The amount you plan to borrow from the bank is:

= Cost of house - down payment

= 127,242 - 30,313

= $96,929

The amount to be paid is constant and so is an annuity. The loan amount is the present value of this annuity.

Term = 20 * 12 = 240 months

Interest = 18% / 12 = 1.5% monthly

Present value of annuity = Annuity * ( 1 - (1 + rate) ^-number of periods) / rate

96,929 = Annuity * (1 - (1 + 1.5%) ⁻²⁴⁰) / 1.5%

96,929 = Annuity * 64.79573209

Annuity = 96,929 / 64.79573209

= $1,495.92

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Consider the following reaction: . so2cl2(g)⇌so2(g)+cl2(g) . a reaction mixture is made containing an initial [so2cl2] of 2.2×10−2m . at equilibrium, [cl2]= 1.3×10−2m .. calculate the value of the equilibrium constant (kc).

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