Chemistry: Consider the reaction: 3a +5b + 1c -- 2d + 1e if you have 6 moles of reactant a and excess of b and c, how much product e would be formed? show work so i can understand .

Consider the reaction: 3a +5b + 1c -- 2d + 1e if

Ответ:

iBrain

01.01.2022

3A=6 mol
A = 6/3
A = 2 mol

E= 2 mol

thats what I learned from school, but its been 3 months since I graduated, I hope I'm not making any mistake
Consider the reaction: 3a +5b + 1c --> 2d + 1e if you have 6 moles of reactant a and excess of

Consider the reaction: 3a +5b + 1c --> 2d + 1e if you have 6 moles of reactant a and excess of

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Ответ:

cuppykittyy

01.01.2022

Chemistry

2 moles of 'E' will be formed.

Explanation:

Reaction follows:

$3A+5B+1C\rightarrow 2D+1E$

By Stoichiometry,

3 moles of 'A' is producing 1 mole of 'E'

Therefore, 6 moles of A will produce = $\frac{1}{3}\times 6=2$ moles of 'E'

6 moles of reactant 'A' is producing 2 moles of 'E' for a given reaction.

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Ответ:

iamasia06

03.09.2022

Chemistry

18,500

Explaination:

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Consider the reaction:
3a +5b + 1c --> 2d + 1e
if you have 6 moles of reactant a and excess of b and c, how much product e would be formed? show work so i can understand .

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Consider the reaction: 3a +5b + 1c --> 2d + 1e if you have 6 moles of reactant a and excess of b and c, how much product e would be formed? show work so i can understand .

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Consider the reaction:
3a +5b + 1c --> 2d + 1e
if you have 6 moles of reactant a and excess of b and c, how much product e would be formed? show work so i can understand .