Consider the reaction: 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.23 moles of HCl(g) react at standard conditions. S°system = J/K

Explanation:

The chemical equation for the reaction is given as:

the entropy change in the system can be calculated as follows:

From the tables; the entropy values where obtained.

∴

i.e the entropy change in the system when 4 moles of HCl is used = -128.9 J/K

∴

when 2.23 moles of HCl is used, Then,

0.5 g/mL float

1.0 g/mL float

2.0 g/mLsink

Explanation:

Those objects will float whose density is less or equal to water density due to lower mass while those object will sink whose density is greater than water because the mass of the object is greater than water. So the density of the object i. e. 0.5 g/mL and 1.0 g/mL will float in the liquid because its density is lower than water which is 1 g/mL while the density of an object i. e. 2.0 g/mL is denser than water so it will sink.