Consider the reaction au(oh)3 + hl — au + 12 + h2o.
label the half-reactions as oxidation (use "o") or reduction (use "r").
21 +2 +2e
aut3 + 3e → au
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Ответ:
2l- = l2 + 2e- (O)
Au+3 + 3e- = Au (R)
Explanation:
I just answered the question.
Ответ:
All of them apply according to the exam your are on because they all need concentration to work up the certain chemical
Explanation
The physical properties of a solution are not affected by the concentration of the components.
Boiling points and freezing points of solutions change as the concentration of the solute changes.
Moles of solute = (Liters of solution) x (Molarity of solution)
(Initial Concentration)(Initial Volume) = (Final Concentration) (Final Volume)
Concentration affects if an acid is weak or strong.