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jacksonshalika
19.07.2019 •
Chemistry
Determine the number of moles nh41+ in 3 moles of (nh4)3po4.
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Ответ:
(NH₄)₃PO₄ → 3NH₄⁺ + PO₄³⁻
The stoichiometric ratio between (NH₄)₃PO₄ and NH₄⁺ is 1 : 3
Hence, moles of (NH₄)₃PO₄ / moles of NH₄⁺ = 1 / 3
moles of (NH₄)₃PO₄ = 3 mol
Hence, moles of NH₄⁺ = moles of (NH₄)₃PO₄ x 3
= 3 mol x 3
= 9 mol
Hence, 3 moles of (NH₄)₃PO₄ give 9 moles of NH₄⁺.
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