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awesomegrill
19.02.2021 •
Chemistry
Drag each label to the correct location.
We use specific words to describe each type of change in state. Label the arrows to describe the changes of state they
represent
gas
liquid
solid
melting freezing condensation
evaporation sublimation
deposition
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Ответ:
solid —> liquid = melting
liquid —> solid = freezing
solid —> gas = sublimation
gas —> liquid = condensation
gas —> solid = deposition
Ответ:
Answer : The percent yield of
is, 24.44 %
Explanation :
First we have to calculate the moles of 3.81 g and 2.86 g of
.
Moles of
reacted = 0.045 - 0.034 = 0.011 g
Now we have to calculate the moles of![H_2CO_3](/tpl/images/0016/3918/9a12c.png)
The balanced chemical reaction will be,
From the balanced reaction, we conclude that
As, 2 moles of
react to give 1 mole of ![H_2CO_3](/tpl/images/0016/3918/9a12c.png)
So, 0.011 moles of
react to give
mole of ![H_2CO_3](/tpl/images/0016/3918/9a12c.png)
Now we have to calculate the mass of![H_2CO_3](/tpl/images/0016/3918/9a12c.png)
The actual yield of
= 0.341 g
If whole of
have reacted then
produced.
From the balanced reaction, we conclude that
As, 2 moles of
react to give 1 mole of ![H_2CO_3](/tpl/images/0016/3918/9a12c.png)
So, 1 mole of
react to give 0.5 mole of ![H_2CO_3](/tpl/images/0016/3918/9a12c.png)
And, 0.045 mole of
react to give
mole of ![H_2CO_3](/tpl/images/0016/3918/9a12c.png)
The mass of
produced.
The theoretical yield of
= 1.395 g
Now we have to calculate the percent yield of![H_2CO_3](/tpl/images/0016/3918/9a12c.png)
Therefore, the percent yield of
is, 24.44 %