cmcdonnell6945
21.01.2021 •
Chemistry
During the phosphatase experiment you will use a 1% w/v of phenolphthalein di-phosphate (PPP). How much PPP do you need to make 750ml of the solution if you only have 25g and you know that the MW of PPP is 478 g/mole
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Ответ:
Explanation:
1 % w/v of phenolphthalein di-phosphate (PPP)
will contain 1 gram of phenolphthalein di-phosphate (PPP) in 100 mL of solution
750 mL solution will contain 7.5 g of PPP
750 mL solution will contain 7.5 / 478 moles of PPP
750 mL solution will contain .0157 moles of PPP
So 7.5 g of PPP or .0157 mole of PPP will be needed .
Ответ:
The CORRECT answers are: lose 2, gain1, lose1, not form an ion, lose 3