![estherstlouis7812](/avatars/45261.jpg)
estherstlouis7812
13.11.2020 •
Chemistry
Essential Question
How does competition affect markets? > How does
the level and intensity of competition affect markets for goods and
services? Suppose you walked into a store selling running shoes under
each of the following conditions. For each example, briefly describe the
variety and quantity of running shoes you would expect to find and the
prices of the shoes.
• This store is one of eight independent stores selling running shoes in
the city.
• This store is one of three stores selling running shoes in the city, but
all three owners secretly work together to increase their profits.
• This store is the only one selling running shoes in the entire city.
Solved
Show answers
More tips
- S Sport How to Choose Tennis Rackets?...
- H Health and Medicine AKDS Vaccination: Ensure Your Child s Safety...
- H Health and Medicine Naskol ko Opasen Ukus Kleshcha i Kak Ego Raspoznat...
- C Computers and Internet How to Delete Your Account on Odnoklassniki...
- H Health and Medicine What to Do When Your Jaw Locks Up?...
- G Goods and services What Are the Most Popular Services?...
- P Philosophy How did the concept of module arise in computer science?...
- F Food and Cooking How to Cook Julienne? Recipes and Tips...
Answers on questions: Chemistry
- M Mathematics Which function represents G (x parentheses, a reflection of x equals (6 1/3) ^ x across the y axis...
- C Chemistry Which is a way that biotechnology has not society? bacteria is used to grow vaccines in large quantities. drugs can be developed without the use of animal research....
- M Mathematics QUESTION IN THE ATTACHMENT...
- S Social Studies You want some points come to my question...
Ответ:
The concentration of NH₄NO₃ required to make [OH⁻] = 1.0 × 10⁻⁵ in a 0.200-m solution of NH₃ is 0.3639 M
Explanation:
Here we have
The reaction of Ammonia and water to produce OH⁻
NH₃ + H₂O → NH₄⁺ + OH⁻
From Henderson-Hasselbalch Equation for bases we have
pOH = pKb + log[acid]/[base]
The concentration of OH⁻ is given as [OH⁻] = 1.0 × 10⁻⁵
Therefore pOH = -log [OH⁻] = -log(1.0 × 10⁻⁵) = 5
The base dissociation constant is given by
kb = [B⁺][OH⁻]/[BOH]
For NH₃, kb = 1.8×10⁻⁵
pKb = -log Kb = 4.74
From the Henderson-Hasselbalch Equation
The acid concentration = [NH₄⁺] and the base concentration = [NH₃] = 0.200 M
pOH = pKb + log ([acid]/[base])
Substituting the values, we have
5 = 4.74 + log ([ NH4+ ]/0.200 M)
[NH4+] = 1.8197×0.200 M = 0.3639 M
NH₄NO₃ → NH₄⁺ + NO₃⁻
Therefore, since one mole of NH₄NO₃, produces one mole of NH₄⁺, the number of moles of NH₄NO₃ required to produce 0.3639 M of NH₄⁺ is 0.3639 M of NH₄NO₃
The concentration of NH₄NO₃ required to make [OH⁻] = 1.0 × 10⁻⁵ in a 0.200-m solution of NH₃ = 0.3639 M