F 100. grams of liquid water at 100.°C and 200. grams of water at 20.0°C are mixed in an insulated container, what will the final temperature of the mixture be? (Specific heat capacity of H 2O( ℓ) = 4.18 J/g•K)

Answer : The final temperature of the mixture will be,

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

where,

= = specific heat of liquid water = Same

= mass of liquid water = 100 g

= mass of water  = 200 g

= final temperature of mixture = ?

= initial temperature of liquid water =

= initial temperature of water =

Now put all the given values in the above formula, we get

Therefore, the final temperature of the mixture will be,

The correct option is this: SOLUTE MOLECULES PULL WATER MOLECULES AWAY FROM THE SURFACE.

For a solute to dissolve in a solvent, the two substance must have similar inter molecular forces. When a solute is input into water, the water molecules and the solutes particles interact together to the extent that the solutes particles pull away from one another as they are surrounded by water molecules and solution is formed.