Fe (s) + S (I) --> Fes (s) In the experiment above, 7.62 g of Fe are allowed to react with 8.67 g of S. How much FeS is
formed?
a) 14.8 g
b) 12.2 g
C) 13.7 g
d) 19.9 g

The concentration of CaCl2 in this solution is 0.563 M

Explanation:

Step 1: Data given

mass of CaCl2 = 23.7 grams

Molar mass of CaCl2 = 110.98 g/mol

mass of water = 375 grams

Molar mass of water = 18.02 grams

Volume of the solution = V

Step 2: Calculate the mass of solution

Mass of the solution = Mass of solute + Mass of solvent

Mass of the solution = 23.7 grams + 375 grams

Mass of the solution = 398.7 grams

Step 3: Calculate the volume

Volume = mass / density

Volume = 398.7 grams / 1.05 mg/mL

Volume = 379.71 mL = 0.3791 L

Step 4: Calculate moles of CaCl2

Number of moles CaCl2 = mass CaCl2 / Molar mass CaCl2

Number of moles CaCl2 = 23.7 grams / 110.98 g/mol

Number of moles CaCl2 = 0.21355 moles

Step 5: Calculate the concentration of CaCl2

Concentration = Number of moles / Volume

Concentration = 0.21355 moles / 0.3791 L

Concentration = 0.563 M

The concentration of CaCl2 in this solution is 0.563 M