Find the mass of 0.763 moles of Gallium.

Explanation:

1 moles Gallium to grams = 69.723 grams

2 moles Gallium to grams = 139.446 grams

3 moles Gallium to grams = 209.169 grams

4 moles Gallium to grams = 278.892 grams

5 moles Gallium to grams = 348.615 grams

6 moles Gallium to grams = 418.338 grams

7 moles Gallium to grams = 488.061 grams

8 moles Gallium to grams = 557.784 grams

9 moles Gallium to grams = 627.507 grams

10 moles Gallium to grams = 697.23 grams

The balanced chemical equation for this process:

$194.51 is the cost that the firm will incur from this use of slaked lime.

Explanation:

The balanced chemical equation for this process

Moles of sulfuric acid = n

Volume of sulfuric acid disposed = V = 1200 gallons = 3.785 × 1200 L = 4,542 L

1 gallon = 3.785 Liter

Morality of the sulfuric acid = M = 1.05 m

According to reaction, 1 mol of sulfuric acid reacts with 1 mole of calcium hydroxide.Then 4,769.1 moles of sulfuric acid will recat with ;

of calcium hydroxide

Mass of 4,769.1 moles of calcium hydroxide:

4,769.1 mol  74 g/mol = 352,913.4 g

=

(1 pound = 453.6 grams)

Cost of 1 pound of slaked lime  = $0.25

Cost of 778.03 pounds of slaked lime  = $0.25 × 778.03 = $194.51

$194.51 is the cost that the firm will incur from this use of slaked lime.