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22.07.2020 •
Chemistry
Find the molecular formula of each compound CCl , 189.83 g/mol C3H2N , 156.23 g/mol
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Ответ:
Explanation:
The given formula is empirical formula
Let the molecular formula of first be
molecular weight = n x ( 12 + 35.5 )
= 47.5 n
Given molecular weight = 189.83 so
47.5 n = 189.83
n = 3.99 or 4 approx
Molecular formula =
= C₄ Cl₄
Let the molecular formula of second compound be
molecular weight = n x ( 3 x 12 +2+14 )
= 52 n
Given molecular weight = 156.23 so
52 n = 156.23
n = 3.0044 or 3 approx
Molecular formula =
= C₉H₆ N₃
Ответ:
En lugar de utilizar las ya conocidas unidades de concentración, para la solubilidad es más común emplear la siguiente: Medimos la solubilidad como la cantidad de gramos del soluto que podemos disolver en 100 gramos de disolvente.
Explanation: