Find volume of 1 mole of helium gas when the pressure is 1.46 atm and the temperature is 270k
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Ответ:
PV = nRT
where P - pressure 1.46 atm x 101 325 Pa/atm = 147 934.5 Pa
V - volume
n - number of moles - 1 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 270 K
substituting these values in the equation
147 934.5 Pa x V = 1 mol x 8.314 Jmol⁻¹K⁻¹ x 270 K
V = 15.17 L
the volume is 15.17 L
Ответ:
the ANSWER IS B
Explanation:
I took the test and got it right it is B