For a given reaction, δh = -19.9 kj/mol and δs = -55.5 j/kmol.

the reaction will have δg = 0 at k.

assume that δh and δs do not vary with temperature.

359 K

Explanation:

The Gibbs free energy can be calculated using the following expression.

ΔG = ΔH - T.ΔS

where,

ΔG is the Gibbs free energy

ΔH is the enthalpy of the reaction

T is the absolute temperature

ΔS is the entropy of the reaction.

When ΔG = 0,

ΔH - T.ΔS = 0

ΔH = T.ΔS

T = ΔH/ΔS = (-19.9 × 10³ J/mol) / (-55.5 J/K.mol) = 359 K