For the decomposition of a peroxide, the
activation energy is 17.4 kJ/mol.
The rate constant at 25 °C is 0.027 s-1.
(a) What is the rate constant at 65 °C?
(b) At what temperature will the rate constant be
25% greater than the rate constant at 25 °C?
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Ответ:
mass molar of gas (Mw):
Mw = 107 g/mol
Explanation:
∴ m gas = 3.82 g
∴ V gas = 0.854 L
∴ T = 302 K
∴ P = 1.04 atm
ideal gas:
PV = RTn∴ n = m / Mw
⇒ PV = RTm/Mw
⇒ Mw = RTm / PV
⇒ Mw = ((0.082 atm.L/K.mol)*(302 K)*(3.82 g)) / ((1.04 atm)*(0.854 L)
⇒ Mw = 106.51 g/mol ≅ 107 g/mol