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lifeisbowling59
18.01.2021 •
Chemistry
For the following reaction, 22.5 grams of iron are allowed to react with 35.0 grams of chlorine gas . iron(s) chlorine(g) iron(III) chloride(s) What is the maximum mass of iron(III) chloride that can be formed
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Ответ:
53.31g of FeCl3
Explanation:
The equation of the reaction is given as;
2Fe(s) + 3Cl2(g) --> 2FeCl3(s)
From the stochiometry of the reaction;
2 mol : 3 mol : 2 mol
112g : 213g : 324.4g
Converting the masses given to moles;
Number of moles of Fe = mass / molar mass = 22.5 / 56 = 0.4018
Number of moles of Cl2 = mass / molar mass = 35 / 71 = 0.4930
In this reaction, the limiting reactant is Cl2
213 g of Cl2 produces 324.4g of FeCl3,
35g of Cl2 would produce xg of FeCl3
213 = 324.4
35 = x
x = (35 * 324.4) / 213 = 53.31g
Ответ:
Step-by-step explanation:
I don't know