Chemistry: For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a closed container are 4.00 atm and 2.00 atm, respectively, what is the approximate equilibrium partial pressure of H2S?

For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp - id222225539939, nyiamcbride5630

Ответ:

idcatall5

21.01.2022

The approximate equilibrium partial pressure of H_2S is 3.92 atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

$K_p=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

$1.5\times 10^{-5}=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

On reversing the reaction:

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

initial pressure 4.00atm 2.00 atm 0

eqm (4.00-2x)atm (2.00-x) atm 2x atm

$K_p=\frac{[H_2S]^2}{[H_2]^2\times [S_2]}$

$K_p'=\frac{1}{K_p}=0.67\times 10^5$

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

$0.67\times 10^5=\frac{2x]^2}{[4.00-2x]^2\times [2.00-x]}$

x=1.96

$[H_2S]=2x=2\times 1.96=3.92 atm$

Thus approximate equilibrium partial pressure of H_2S is 3.92 atm

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Ответ:

smolemily

27.05.2022

Chemistry

Explanation:

Balance Chemical Equation:

A balanced chemical equation is that in which the the number of the reactant atoms equal to the number of the product atom.

For example if the oxygen at the reactant side is 4, the number of oxygen should be 4 on the product side.

The complete answer is in attachment

Equation 1:

2 is the correct number

In the equation look for the number of Carbon on product side

C = 4 so it should be 4 on reactant side too

So,

by putting 2 in Coefficient location the number of C become equal on reactant as well as product side.

____________________

Equation 2:

12 on reactant side and 6 on product side is the correct number

In the equation look for the number of Hydrogen (H) on product side

it is H = 12 so it should be 12 on reactant side too

Then look for the number of Chlorine (Cl) on reactant side

C = 12 so it should be 12 on Product side too

So,

by putting 12 in Coefficient location of the reactant side and 6 on product side the number of H and Cl become equal on reactant as well as product side.

______________________

Equation 3:

5 is the correct number

In the equation look for the number of Oxygen on product side

O = 12 so it should be 12 on reactant side too

So,

by putting 5 in Coefficient location the number of O become equal on reactant as well as product side.

______________________

Equation 4:

3 on reactant side and 1 on product side is the correct number

In the equation look for the number of Chlorine (Cl) on product side

it is Cl = 6 so it should be 6 on reactant side too

Then look for the number of Calcium (Ca) on reactant side

Ca = 1 so it should be 1 on reactant side too

So,

by putting 3 in Coefficient location of the reactant side and 1 on product side the number of Cl and Ca become equal on reactant as well as product side.

____________________

Equation 5:

4 and 7 on reactant side is the correct number

In the equation look for the number of Sulfur (S) on product side

it is S = 4 so it should be 4 on reactant side too

Then look for the number of Oxygen (O) on product side

O = 14 so it should be 14 on reactant side too

So,

by putting 4 and 7 in Coefficient location of the reactant side so the number of S and O become equal on reactant as well as product side.

Balancing chemical equations place the number in the correct coefficient location to make each equat

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For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a closed container are 4.00 atm and 2.00 atm, respectively, what is the approximate equilibrium partial pressure of H2S?

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