Gaseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 10.1 g of methane is mixed with 58. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.

Explanation:

CH₄ + 2O₂ = CO₂ + 2H₂O

1 mole + 2 moles  = 1 moles + 2 moles

10.1 gm of methane = 10.1 / 16 = .63 moles of methane

58 g of oxygen = 58 / 32 = 1.8125 moles of oxygen

1 moles of methane reacts with 2 moles of oxygen to make 1 mole of CO₂

.63 moles of methane reacts with 1.26 moles of oxygen to make .63 mole of

CO₂

so CO₂ formed = .63 moles

.63 x 44 = 27.7 grams of CO₂

It is the minimum amount of analyte that produces a signal which can be measured with reasonable accuracy - LOQ

The concentration is equal to three times the standard deviation of the signal from the blank divided by the slope of the calibration curve - LOD

The concentration is equal to 10 times the standard deviation of the signal from the blank divided by the slope of the calibration curve - LOQ

It is the minimum amount of analyte that produces a signal that is significantly different from the blank - LOD

Explanation:

We define the limit of detection has the lowest amount of analyte that produces a signal that is significantly different from a blank solution ( the absence of the substance). It is calculated as three times the standard deviation of the signal from the blank divided by the slope of the calibration curve.

The limit of quantitation (LOQ) is defined as the minimum amount of analyte that produces a signal which can be measured with reasonable accuracy. It is measured as 10 times the standard deviation of the signal from the blank divided by the slope of the calibration curve.