Chemistry: Given the balanced equation 2(h2 s) + 3(o2) = 2(s o2) + (h2 o) what is the correct mole ratio set? h2 s: s o2 = 2: 2 , o2: h2 o 2: 2, 3: 2 2: 3, 3: 2 4: 4, 5: 4 4: 6, 4: 4

Given the balanced equation 2(h2 s) + 3(o2) =

sumitshekhar348

01.03.2021

Answer : The amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

Explanation : Given,

Density of air = 1.2kg/m^3=1.2g/L (1kg/m^3=1g/L)

First we have to calculate the mass of air.

$\text{Mass of air}=\text{Density of air}\times \text{Volume of air}$

$\text{Mass of air}=1.2g/L\times 6.0L$

$\text{Mass of air}=7.2g$

Now we have to calculate the amount of formaldehyde.

Permissible exposure level of formaldehyde = 0.75 ppm = $\frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $7.2g\times \frac{0.75g\text{ of formaldehyde}}{10^6g\text{ of air}}$

Amount of formaldehyde in 7.2 g of formaldehyde = $5.4\times 10^{-6}g$

Thus, the amount of formaldehyde permissible are, $5.4\times 10^{-6}g$

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