Given the balanced neutralization equation from part B, how many moles of potassium hydroxide (KOH) are required to neutralize 4.5 mol of sulfuric acid (H2SO4)? Assume that the sulfuric acid completely dissociates in water.
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Ответ:
9 moles of KOH
Explanation:
Let's begin with the neutralization reaction.
Neutralization reaction always gives as product, water and a salt
2KOH + H₂SO₄ → 2H₂O + K₂SO₄
Ratio in the reactant side is 1:2. We can determine this rule of three:
1 mol of sulfuric acid can react with 2 moles of potassium hydroxide
Therefore, 4.5 moles sulfuric acod wil react with (4.5 . 2) /1 = 9 moles of KOH
Ответ:
Cansada
Explanation: