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charlesiarenee0
14.04.2020 •
Chemistry
Given the following reaction:
Zn + CuCl2 —> ZnCl2 + Cu
How many moles of ZnCl2 will be produced from 23.0g of Zn, assuming CuCl2 is available in excess?
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Ответ:
The answer to your question is 0.35 moles of ZnCl₂
Explanation:
Data
moles of ZnCl₂ = ?
mass of Zn = 23 g
mass of CuCl₂ = excess
Balanced chemical reaction
Zn + CuCl₂ ⇒ ZnCl₂ + Cu
Process
1.- Convert the mass of Zn to moles
-Look for the atomic mass of Zn
Atomic mass = 65.4 g
-Convert the grams to moles
65.4 g 1 mol
23 g x
x = (23 x 1)/65.4
x = 23 / 65.4
x = 0.35 moles of Zn
2.- Calculate the moles of ZnCl₂ using proportions and cross multiplication, and the coefficients of the balanced chemical reaction.
1 mol of Zn 1 mol of ZnCl₂
0.35 moles of Zn x
x = (0.35 x 1) / 1
x = 0.35 moles of ZnCl₂
Ответ:
The correct answer is C
Explanation: I took the test