Chemistry: How hot will a 2.3 liter balloon have to get to expand to a volume of 7 L? Assume that the initial temperature of the balloon is 25 C?

How hot will a 2.3 liter balloon have to get to expand

haileesprague1578

25.01.2022

Answer : The final temperature of balloon will be, 907 K

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=2.3L\\T_1=25^oC=(25+273)K=298K\\V_2=7L\\T_2=?$

Putting values in above equation, we get:

$\frac{2.3L}{298K}=\frac{7L}{T_2}\\\\T_2=906.95K\approx 907K$

Therefore, the final temperature of balloon will be, 907 K

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hernandez48tur

12.12.2022

1 mol of carbonate to 2 mol of acid

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}$

a) $\text{Moles of carbonate}=\frac{0.2moldm^{-3}\times 25cm^3}{1000}=0.005mol$

b) $\text{Moles of acid}=\frac{0.5moldm^{-3}\times 20cm^3}{1000}=0.01mol$

Thus the mole ratio of carbonate to acid is = $\frac{0.005}{0.01}=\frac{1}{2}$

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