How long does it take light to travel across the width of a pb nucleus of radius 7.1 fm?
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Ответ:
The light takes 4.73×10⁻²³ s to travel across the width of the Pb nucleus.
Explanation:
Given :
Radius of Pb nucleus = 7.1 fm
Also, The conversion of fm into m is shown below:
1 fm = 10⁻¹⁵ m
The radius of Pb nucleus = 7.1×10⁻¹⁵ m
The width of Pb nucleus (diameter) = 2× Radius of the nucleus
Thus,
Width of Pb nucleus = 2×7.1×10⁻¹⁵ m = 14.2×10⁻¹⁵ m
The Speed of light = 3×10⁸ m/s
The formula for Speed is shown below:
Time can be calculated from the above formula as:
Applying values in the above formula as:
Time = 4.73×10⁻²³ s
Ответ:
(.222mol K)(3mol K2O/6mol K) = .111mol K2O
(0.914mol K2O)(2mol B/3mol K2O) = .609mol B
(.609mol B)(10.8g/mol B) = 6.58g B