How many carbon atoms are in 1.25 mol of silver acetate?
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Ответ:
PV = nRT
n = PV / RT
n = (1.4 * 226.4) / (0.082 *(27 + 273.15))
n = 12.88
Next, we use the given percentages to find the moles of helium present
Moles of helium = 0.655 * 12.88
Moles of helium = 8.44
Next, we use the formula:
Mass = moles * molar mass
Mass of helium = 8.44 * 4
Mass of helium = 33.76 grams