How many grams of calcium bromide are in 50.0 ml of a 0.25 m calcium bromide solution?
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Ответ:
CaBr2 = 40 + 80 * 2 = 200 g / mol
Volume = 50.0 mL : 0.05 L
Molarity = 0.25 M
Mass of solute = ?
M = m / mm * V
0.25 = m / 200 * 0.05
m = 0.25 * 200 * 0.05
m = 2.5 g of CaBr2
hope this helps!.
Ответ: