How many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptaflouride?
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Ответ:
Atomic weights: Cs=133, F=19, CsF=152, Xe=131, CsF=152, CsXeF7=397 73.1gCsXeF7 x 1molCsXeF7/397gCsXeF7 x 1molCsF/1molCsXeF7 x 152gCsF/1molCsF = 28.0g CsF to three significant figures
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Ответ:
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