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30.06.2019 •
Chemistry
How many grams of feo would be needed to make 234.2 grams of fe in the chemical reaction 4feo = fe3o4 + fe? show your work.
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Ответ:
1,203.84 grams of FeO will be needed.
Explanation:
Moles of iron =![\frac{234.2 g}{56 g/mol}=4.18 mol](/tpl/images/0034/6157/03405.png)
According to reaction, 1 mol of iron is obtained from 4 moles of ferrous oxide.
Then 4.18 moles of iron will be obtained from:
Mass of 16.72 moles of ferrous oxide:
16.72 mol × 72 g/mol = 1,203.84 g
1,203.84 grams of FeO will be needed.
Ответ: