How many grams of magnesium chloride are in 1.33 mol of mgcl2?
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Ответ:
126.63 g.
Explanation:
Knowing that the no. of moles can be calculated using the relation:no. of moles (n) = mass/molar mass
no. of moles MgCl₂= 1.33 mol & molar mass of MgCl₂ = 95.211 g/mol.
∴ mass = no. of moles * molar mass = (1.33 mol)*(95.211 g/mol) = 126.63 g.
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