How many grams of nacl do you need to prepare 200 ml of a 5m solution? the molecular weight of nacl is 58.4 g/mol. smol 0.2l-1mol nacl lib imol naclx 8.glol nacl mol 58.19 nac

58.4 grams of NaCl is needed to prepare 200 ml of a 5M solution.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the number of moles by the molar mass of the substance as follows:Mass of substance = no. of moles × molar massHowever, we need to calculate the number of moles in 200 ml of a 5M solution of NaCl by multiplying the molarity by the volume. Volume = 200mL = 0.2Lno. of moles of NaCl = 0.2L × 5Mno. of moles = 1 molMolar mass of NaCl is given as 58.4g/molMass of NaCl = 1 × 58.4Mass of NaCl = 58.4grams. Therefore, 58.4 grams of NaCl is needed to prepare 200 ml of a 5M solution.

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The answer to your question is: 58.4 g of NaCl

Explanation:

Data

Volume = 200 ml = 0.2 l

Concentration = 5M

MW = 58.4 g

mass NaCl = ?

Formula

             Molarity = (# of moles ) / volume

             # of moles = Molarity x volume

             # of moles = 5 x 0.2

             # of moles = 1

              58.4 g 1 mol

              x            1 mol

              x = (1 x 58.4) / 1

             x = 58.4 g of NaCl

Its 2 man

Explanation: