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23.05.2020 •
Chemistry
How many grams of silver chromate will precipitate when 150. mL of .500 M silver nitrate are added to 100. mL of .400 M of potassium chromate
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Ответ:
2Ag^+ +CrO2/4→Ag2CrO4(s)↓
Explanation:
Silver chromate
will deposit from solution as a fine brick-red precipitate with alacrity; the material is exceptionally insoluble.
And thus we calculate the equivalent quantities of
silver ion
and
chromate ion.
Moles of silver nitrate =0.150 ⋅ L × 0.500 ⋅ mol ⋅ L^−1 = 0.0750 ⋅ mol . Moles of potassium chromate = 0.100 ⋅ L × 0.400 ⋅ mol ⋅ L^−1 = 0.0400 ⋅ mol
.
Clearly, silver nitrate is the limiting reagent, as there is a stoichiometric excess of chromate ion.
And thus we should get a mass of
1/2 × 0.0750 ⋅ mol × 331.73 ⋅ g ⋅ mol^−1 = 12.4 ⋅ g
with respect to Ag2CrO4.
https://api-project-1022638073839.appspot.com/questions/how-many-grams-of-silver-chromate-will-precipitate-when-150-ml-of-0-500-m-silver#413727
Ответ:
atomic number for iron : 26
number of electrons in a neutral iron atom : 26