how many grams of zinc will be formed if 32 G of copper reacts with zinc nitrate copper 1 nitrate is the other product

Mass = 32.69 g

Explanation:

Given data:

Mass of copper = 32 g

Mass of zinc formed = ?

Solution:

Chemical equation:

Cu + Zn(NO₃)₂     →       Cu(NO₃)₂ + Zn

Number of moles of copper:

Number of moles = mass/molar mass

Number of moles = 32 g/ 63.55 g/mol

Number of moles = 0.5 mol

now we will compare the moles of zinc with copper.

           Cu          :           Zn

            1            :            1

          0.5          :         0.5

Mass of Zn:

Mass = number of moles × molar mass

Mass = 0.5 mol  × 65.38 g/mol

Mass = 32.69 g

18. E. 0%

19. D. 25%

Explanation:

Question 18:

Let's use "B" to represent the dominant allele of "light blue skin", and

"b" for recessive "light green skin".

Squidward => BB - light blue skin

Squidward's bride => bb - light green skin

When they cross, they will have the following offsprings:

(BB) × (bb) - Parent

(Bb) (Bb) (Bb) (Bb) - Offspring

All the offspring would be light green skin. The dominant allele of light green skin will express itself over the recessive allele.

Therefore, the chances of Squidward and his bride having light green skin is 0%

Question 19:

Squidward's son => Bb - light blue skin

Squidward's son's bride => Bb - light blue skin

(Bb) × (Bb) - parent

(BB) (Bb) (Bb) (bb) - offspring

They will have the following offspring:

BB and Bb - light blue - 75%

bb - light green - 25%

Chance of having offspring with light green skin is 25%