How many iodide ions are present in 65.5ml of .210 m ali3 solution
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Ответ:
Explanation:
Molarity of the solution = 0.210 M
Volume of the solution = 65.5 ml = 0.0655 L
Moles of aluminum iodide= n
n = 0.013755 moles of aluminum iodide
1 mole of aluminum iodide contains 3 moles of iodide ions:
Then 0.013755 moles of aluminum iodide will contain:
Number of iodide ions in 0.041265 moles:
Ответ: