How many liters are there in 122 grams of cu(no3)2?

0.4 mL is the volume of 122 g of Cupper (II) nitrate

Explanation:

You have to work with density, to solve the problem.

Density is the relation mass / volume

Cupper (II) nitrate density = Cupper (II) nitrate mass / Cupper (II) nitrate volume

3.05 g/mL = 122 g / Cupper (II) nitrate volume

Cupper (II) nitrate volume = 122 g / 3.05 g/mL

Cupper (II) nitrate volume = 0.4 mL

The correct answer is

Aluminum, boron, and gallium are likely together in one group because they have the same number of valence electrons, and carbon and germanium are likely together in another group because they have the same number of valence electrons.

This is the only one that makes sense after reviewing the data. Hopefully this helps! Feel free to mark as brainliest!