How many liters of ch4 are needed to produce 5.46 kg of h2 using the steam reformation process? data: p = 2280 mmhg t = 700 degrees celsius steam reformation: ch4 (g) + h2o (g) = co (g) + 3h2 (g)
Solved
Show answers
More tips
- C Computers and Internet How to Format Your C Drive: Detailed Guide and Tips...
- F Food and Cooking How to Properly Cook Buckwheat?...
- F Food and Cooking How Many Grams Are In a Tablespoon?...
- L Leisure and Entertainment Carving: History and Techniques for Creating Vegetable and Fruit Decorations...
- P Photography and Videography How to Choose the Perfect Photo Paper for Your Images?...
- H Health and Medicine What vaccines do children need?...
- H Health and Medicine Reasons for the Appearance of Warts: Everything You Need to Know...
- A Art and Culture How to Learn Screaming: Step-by-Step Guide for Beginners...
- H Health and Medicine Contraceptive Pills After 35: The Importance Of Choosing The Right Medication...
- C Computers and Internet How to Choose a Monitor?...
Answers on questions: Chemistry
- G Geography Which of the following areas has the lowest population density? papua new guinea fiji islands solomon islands antarctica...
- B Biology Which of the space missions involved the deployment of lunar rover...
- M Mathematics Question 12 a parachutist s rate during a free fall reaches 198 kilometers per hour. what is this rate in meters per second? at this rate, how many meters will the...
- S Spanish María: ¿Cuando cierra la exhibición? Mateo: el martes que viene....
Ответ:
2.40 × 10³ L
Step-by-step explanation:
You know that you will need a balanced equation with masses, moles, and molar masses, so gather all the information in one place.
M_r: 2.016
CH₄ + H₂O ⟶ CO + 3H₂
m/g: 5460
Step 1. Convert grams of H₂ to moles of H₂
1 mol H₂ = 2.016 g H₂
Moles of H₂ = 5460 × 1/2.016
Moles of H₂ = 2708 mol H₂
Step 2. Convert moles of H₂ to moles of CH₄.
The molar ratio is 1 mol CH₄ to 3 mol H₂
Moles of CH₄ = 2708 × 1/3
Moles of CH₄ = 902.8 mol CH₄
Step 3. Use the Ideal Gas Law to calculate the volume.
pV = nRT Divide each side by V
V = (nRT)/p
n = 902.8 mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = (700 + 273.15) K = 973.15 K
p = 2280 mmHg × 1 atm/760 mmHg = 3.000 atm
V = (902.8 × 0.082 06 × 973.15)/3.000
V = 72 090/3.000
V = 2.40 × 10³ L
Ответ: