How many milliliters of 0.0850 m naoh are required

Ответ:

cee837

23.01.2022

Chemistry

The given question is incomplete. The complete question is:

How many milliliters of 0.0850 M NaOH are required to titrate 25.0 mL of 0.0720 M HBr to the equivalence point?

21.2 ml

Explanation:

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HBr

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=0.0720M\\V_1=25.0mL\\n_2=1\\M_2=0.0850M\\V_2=?mL$

Putting values in above equation, we get:

$1\times 0.0720\times 25.0=1\times 0.0850\times V_2\\\\V_2=21.2mL$

Thus 21.2 ml of 0.0850 M NaOH are required to titrate 25.0 mL of 0.0720 M HBr to the equivalence point

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Ответ:

kaelynnmarie1135

29.11.2022

Chemistry

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Explanation:

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How many milliliters of 0.0850 m naoh are required to titrate 25.0 ml of to the equivalence point?

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