Thejollyhellhound20
07.10.2019 •
Chemistry
How many ml of 0.100 m naoh are needed to neutralize 50.00 ml of a 0.150 m solution of ch3co2h, a monoprotic acid?
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Ответ:
C = n/V
n = 0,15 mol/dm³ × 0,05dm³
n = 0,0075 mol CH₃COOH
CH₃COOH + NaOH > CH₃COONa + H₂O
1 mol1 mol
1 mol CH₃COOH 1 mol NaOH
0,0075 mol CH₃COOH --- X
X = 0,0075 mol NaOH
V = n/C
V = 0,0075/0,1
V = 0,075 dm³ = 75cm³ = 75 mL
Ответ:
hope my answer helps you :D
Explanation:
c. 2 beats