How many ml of .450 m hcl is needed to neutralize 30ml of .150 m ba(oh)2
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Ответ:
P₂ = 1312.9 atm
Explanation:
Given data:
Initial temperature = 25°C
Initial pressure = 1250 atm
Final temperature = 40°C
Final pressure = ?
Solution:
Initial temperature = 25°C (25+273.15= 298.15 K)
Final temperature = 40°C (40+273.15 = 313.15 k)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
1250 atm /298.15 K = P₂/ 313.15 k
P₂ = 1250 atm × 313.15 k / 298.15 K
P₂ = 391437.5 atm. K /298.15 K
P₂ = 1312.9 atm