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whitakers87
23.11.2019 •
Chemistry
How many molecules are in 95.75 g of calcium chloride?
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Ответ:
5.195 x 10²³ molecules ≅ 5.2 x 10²³ molecules.
Explanation:
It is known that every 1.0 mole of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³).We need to calculate the no. of moles in 95.75 g of CaCl₂ using the relation:n = mass/molar mass = (95.75 g)/(110.98 g/mol) = 0.86 mol.
Using cross multiplication:
1.0 mole of CaCl₂ contains → 6.022 x 10²³ molecules.
0.86 mole of CaCl₂ contains → ??? molecules.
∴ 95.75 g of CaCl₂ (0.86 mole) contain = (0.86 mol)(6.022 x 10²³) = 5.195 x 10²³ molecules ≅ 5.2 x 10²³ molecules.
Ответ:
I think the answer is Chemists have selected a number of particles with which to work. Hope it helps and stay healthy :)