How many molecules of c2h4cl2 can be prepared from 15 c2h4 molecules and 8cl2 molecules?
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Ответ:
8 molecules of C₂H₄Cl₂
Explanation:
Molecules of C₂H₄ = 15 molecule
Molecules of Cl₂ = 8 molecules
Molecules of C₂H₄Cl₂ =?
First of all we will write the balance chemical equation,
C₂H₄ + Cl₂ → C₂H₄Cl₂
we are given 8 molecules of Cl₂ and 15 molecules of C₂H₄, which means that 8 molecules of chlorine react with 8 molecules of C₂H₄ and will limit the reaction product. The seven molecules of C₂H₄ will remain unreactive. So , the chlorine will be the limiting reactant.
8 molecules of Cl₂ × 1 mole of C₂H₄Cl₂/ 1 mole of Cl₂
8 molecules of C₂H₄Cl₂
Ответ:
the volume of the cube in centimeters cubed is 19.68