![happysage12](/avatars/24792.jpg)
happysage12
20.01.2021 •
Chemistry
How many moles are in 3.57 x 10^32 particles?
Solved
Show answers
More tips
- T Travel and tourism How to Use a Compass: A Beginner s Guide...
- C Computers and Internet Porn Banner: What It Is and How to Get Rid Of It?...
- F Food and Cooking How many stages of coffee roasting are there?...
- F Food and Cooking From Latte to Espresso: Which Coffee Drink is the Most Popular on Earth?...
- F Food and Cooking Experts Name Top 5 Healthiest Teas...
- C Computers and Internet Google Search Tips and Tricks: Everything You Need to Know...
- H Health and Medicine Discover the Hidden Principles and Real Results of the Japanese Diet...
- H Health and Medicine Liver Cleansing - Rejuvenation for the Body?...
- S Style and Beauty Is Photoepilation the Solution to Unwanted Hair Forever?...
- S Style and Beauty Unbelievable Hairstyles for Long Hair - 2021 Trends...
Answers on questions: Chemistry
- M Mathematics Write a multipication expression that shows...
- H History 10 points pls help in the early years of World War I, from 1914 to 1916, the United States a. Became an arsenal for the Allies b. Did not clearly declare neutral...
- B Biology Present at least one paragraph describing your experience will the illusions lab. What are your thoughts about the experience? Which illusion was your favorite?...
Ответ:
B = b -a/RT
C = b^2
a = 1.263 atm*L^2/mol^2
b = 0.03464 L/mol
Explanation:
In the given question, we need to express the van der Waals equation of state as a virial expansion in powers of 1/Vm and obtain expressions for B and C in terms of the parameters a and b. Therefore:
Using the van deer Waals equation of state:
With further simplification, we have:
Then, we have:
Therefore,
Using the expansion:
Therefore,
Thus:
Using the virial equation of state:
Thus:
Comparing equations (1) and (2), we have:
B = b -a/RT
C = b^2
Using the measurements on argon gave B = −21.7 cm3 mol−1 and C = 1200 cm6 mol−2 for the virial coefficients at 273 K.
a = (b-B)*RT = (34.64+21.7)*(1L/1000cm^3)*(0.0821)*(273) = 1.263 atm*L^2/mol^2