How many moles of benzoic acid are present? How many moles of sodium bicarbonate are contained in 1 ml of 10% aqueous solution? (A 10% solution has 1 gram of solute in 9 mL of solvent.) Is the amount of sodium bicrbonate sufficient to react with benzoic acid.

Complete Question

 In experiment 1, how many moles of benzoic acid are present? How many moles of sodium bicarbonate are contained in 1 ml of 10% aqueous solution? (A 10% solution has 1 gram of solute in 9 mL of solvent.) Is the amount of sodium bicarbonate sufficient to react with benzoic acid. The amount of Benzoic Acid in ex. 1 is 0.060 grams

No of  moles of benzoic acid  present

Number of moles of  sodium bicarbonate present  

Yes the is sufficient sodium bicarbonate to react with Benzoic acid

Explanation:

From the question we are told that

        The mass of Benzoic acid is  

The number of moles of  Benzoic acid is  

                 

where is the molar mass of Benzoic acid which is a constant with values

         

So  

         

         

the density of the solution of sodium bicarbonate is  

     

     

The mass of  sodium bicarbonate is  

       

       

The molar mass of  sodium bicarbonate is   a constant  with value

         

The number of moles of sodium bicarbonate is  

         

       

       

So the number of moles of  Benzoic acid and  sodium bicarbonate that react are approximately in a 1:1 ratio so we can conclude that there is sufficient  sodium bicarbonate to react Benzoic acid

See below

Step-by-step explanation:

Polynomials are:

consisting of indeterminates and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.

According to definition of polynomials we can state:

Numbers 2, 5 and 6 are polynomialsNumbers 1, 3 and 4 are not polynomials as they have radicals, negative integer exponents and involve division operation.