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tylorwsimmons
29.09.2019 •
Chemistry
How many moles of calcium chloride would be produced by the reaction below when 53.2 milliliters of water are produced, if the density of water is 0.987 g/ml? show all steps of your calculations as well as the final answer hcl + ca(oh) 2 → h2o + cacl2
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Ответ:
Mass of water = .987 * 53.2 = 52.5084 g
Mole of water = 52.5084g/ 18= 2.917 mol
Mole of CaCl2= 2.917 mol / 2 = 1.458
This answer will definitely help you. Regards!
Ответ:
Correct a₂ > a₁
Explanation:
Given:
Tony mass = m₁ = 50 kg
Sam mass = m₂ = 45 kg
According to Newton's second law, the formula for calculating force is:
F = m · a
In this case we have the same force for both
F = m₁ a₁ = m₂ a₂ => a₁ / a₂ = m₂ / m₁ = 45 / 50 = 9 / 10 = 0.9
a₁ = 0.9 a₂ => a₁ = 90% of a₂ => a₂ > a₁
a₂ > a₁
God is with you!!!