How many moles of chloride ions are in 0.2550 g - id025502040364, exoticbunnylover123

Ответ:

dorothybean

01.01.2022

Chemistry

Explanation:

It is known that number of moles is the amount of mass present in a given molar mass of the substance.

Mathematically, No. of moles = $\frac{mass}{\text{molar mass}}$

We are given that mass of $AlCl_{3}$ is 0.255 g and molar mass of $AlCl_{3}$ is 133.34 g/mol.

Therefore, number of moles of $AlCl_{3}$ is calculated as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.255 g}{133.34 g/mol}$

= $1.912 \times 10^{-3}$ mol

Since, there are three chlorine atoms present in one mole of $AlCl_{3}$ . Therefore, moles of chlorine ions present in given 0.255 g will be calculated as follows.

$3 \times 1.912 \times 10^{-3}$ mol

= $5.736 \times 10^{-3} mol$

Thus, we can conclude that $5.736 \times 10^{-3} mol$ chloride ions are in 0.2550 g of aluminum chloride using $AlCl_{3}$ 's molar mass of 133.34 g/mol.

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How many moles of chloride ions are in 0.2550 g of aluminum chloride using alcl3 's molar mass of 133.34 g / mol: ?

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