Chemistry: How many moles of co2 are produced when 45.0g of c6h6 react completely in the following equation? 2c6h6+ 15o2 → 12co2 + 6h2o

How many moles of co2 are produced when 45.0g of

Ответ:

anonymous1813

12.03.2022

Chemistry

Answer : The moles of CO_2 produced are, 3.462 moles.

Explanation : given,

Mass of C_6H_6 = 45.0 g

Molar mass of C_6H_6 = 78 g/mole

First we have to calculate the moles of C_6H_6 .

$\text{Moles of }C_6H_6=\frac{\text{Mass of }C_6H_6}{\text{Molar mass of }C_6H_6}=\frac{45.0g}{78g/mole}=0.577moles$

Now we have to calculate the moles of CO_2

The given balanced chemical reaction is,

$2C_6_H6+15O_2\rightarrow 12CO_2+6H_2O$

From the balanced chemical reaction, we conclude that

As, 2 moles of C_6H_6 react to give 12 moles of CO_2 .

So, 0.577 moles of C_6H_6 react to give $\frac{12}{2}\times 0.577=3.462$ moles of CO_2 .

Therefore, the moles of CO_2 produced are, 3.462 moles.

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Ответ:

hayesvolcano

18.11.2020

Chemistry

The answer is a) N2 (g) + 3H2 (g) = 2NH3 (g) because the number of moles of gas on the right-hand side is less than the number of moles of gas on the left-hand side. When the volume is decreased, the equilibrium would shift to the side with fewer moles of gas.

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How many moles of co2 are produced when 45.0g of c6h6 react completely in the following equation? 2c6h6+ 15o2 → 12co2 + 6h2o

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