How many moles of nitrogen dioxide gas will be produced if 25.0 ml of 2M nitric acid react? Cu + HNO3 = Cu(NO3)2 + NO2 + H2O

0.025 moles of NO₂  will produced

Explanation:

Given data:

Moles of NO₂ formed = ?

Volume of HNO₃ = 25.0 mL

Molarity of HNO₃ = 2 M

Solution:

Chemical equation:

Cu + 4HNO₃   →        Cu(NO₃)₂ + 2NO₂ + 2H₂O

Number of moles of HNO₃:

Molarity = number of moles /  volume in L

2M = number of moles / 0.025 L

Number of moles = 2 M × 0.025 L

Number of moles = 0.05 mol

Now we will compare the moles of HNO₃  with NO₂  from balance chemical equation.

                                  HNO₃            :          NO₂

                                      4                :            2

                                 0.05               :         2/4×0.05 =0.025

0.025 moles of NO₂  will produced.

The limiting reagent refers to the reagent in a multipotent reaction, which will get exhausted as the reaction advances towards completion. In other words, if a chemical reaction exhibits various reagents, then the limiting reagent is the reagent, which will become exhausted first, parting some amount of the other reactants remaining. This is essential to determine, as the concentration of the limiting reagent, which is found in the reaction, will predict that how much product is generated.